Shannon and Risa have some markers in the ratio 3 : 11. Shannon has 64 less markers than Risa. How many markers must Risa give to Shannon so that they will have the same number of markers?
| |
Shannon |
Risa |
Total |
| Before |
3 u |
11 u |
14 u |
| Change |
+ 4 u |
- 4 u |
|
After |
1x7 =
7 u |
1x7 =
7 u |
2x7 =
14 u |
The total number of markers remains unchanged. Make the total number of markers at first and in the end the same. LCM of 2 and 14 is 14.
Difference in the number of markers at first
= 11 u - 3 u
= 8 u
8 u = 64
1 u = 64 ÷ 8 = 8
Number of markers that each of them had in the end
= 14 u ÷ 2
= 7 u
Number of markers that Risa must give to Shannon
= 7 u - 3 u
= 4 u
= 4 x 8
= 32
Answer(s): 32
