Linda and Xandra have some markers in the ratio 3 : 11. Linda has 48 less markers than Xandra. How many markers must Xandra give to Linda so that they will have the same number of markers?
| |
Linda |
Xandra |
Total |
| Before |
3 u |
11 u |
14 u |
| Change |
+ 4 u |
- 4 u |
|
After |
1x7 =
7 u |
1x7 =
7 u |
2x7 =
14 u |
The total number of markers remains unchanged. Make the total number of markers at first and in the end the same. LCM of 2 and 14 is 14.
Difference in the number of markers at first
= 11 u - 3 u
= 8 u
8 u = 48
1 u = 48 ÷ 8 = 6
Number of markers that each of them had in the end
= 14 u ÷ 2
= 7 u
Number of markers that Xandra must give to Linda
= 7 u - 3 u
= 4 u
= 4 x 6
= 24
Answer(s): 24
