Tina and Fanny have some pencils in the ratio 5 : 11. Tina has 66 less pencils than Fanny. How many pencils must Fanny give to Tina so that they will have the same number of pencils?
| |
Tina |
Fanny |
Total |
| Before |
5 u |
11 u |
16 u |
| Change |
+ 3 u |
- 3 u |
|
After |
1x8 =
8 u |
1x8 =
8 u |
2x8 =
16 u |
The total number of pencils remains unchanged. Make the total number of pencils at first and in the end the same. LCM of 2 and 16 is 16.
Difference in the number of pencils at first
= 11 u - 5 u
= 6 u
6 u = 66
1 u = 66 ÷ 6 = 11
Number of pencils that each of them had in the end
= 16 u ÷ 2
= 8 u
Number of pencils that Fanny must give to Tina
= 8 u - 5 u
= 3 u
= 3 x 11
= 33
Answer(s): 33
