Jaslyn and Nicole have some pencils in the ratio 3 : 7. Jaslyn has 56 less pencils than Nicole. How many pencils must Nicole give to Jaslyn so that they will have the same number of pencils?
| |
Jaslyn |
Nicole |
Total |
| Before |
3 u |
7 u |
10 u |
| Change |
+ 2 u |
- 2 u |
|
After |
1x5 =
5 u |
1x5 =
5 u |
2x5 =
10 u |
The total number of pencils remains unchanged. Make the total number of pencils at first and in the end the same. LCM of 2 and 10 is 10.
Difference in the number of pencils at first
= 7 u - 3 u
= 4 u
4 u = 56
1 u = 56 ÷ 4 = 14
Number of pencils that each of them had in the end
= 10 u ÷ 2
= 5 u
Number of pencils that Nicole must give to Jaslyn
= 5 u - 3 u
= 2 u
= 2 x 14
= 28
Answer(s): 28
