Natalie and Jade have some pens in the ratio 3 : 11. Natalie has 80 less pens than Jade. How many pens must Jade give to Natalie so that they will have the same number of pens?
| |
Natalie |
Jade |
Total |
| Before |
3 u |
11 u |
14 u |
| Change |
+ 4 u |
- 4 u |
|
After |
1x7 =
7 u |
1x7 =
7 u |
2x7 =
14 u |
The total number of pens remains unchanged. Make the total number of pens at first and in the end the same. LCM of 2 and 14 is 14.
Difference in the number of pens at first
= 11 u - 3 u
= 8 u
8 u = 80
1 u = 80 ÷ 8 = 10
Number of pens that each of them had in the end
= 14 u ÷ 2
= 7 u
Number of pens that Jade must give to Natalie
= 7 u - 3 u
= 4 u
= 4 x 10
= 40
Answer(s): 40
