Penelope and Hilda have some markers in the ratio 5 : 13. Penelope has 72 less markers than Hilda. How many markers must Hilda give to Penelope so that they will have the same number of markers?
| |
Penelope |
Hilda |
Total |
| Before |
5 u |
13 u |
18 u |
| Change |
+ 4 u |
- 4 u |
|
After |
1x9 =
9 u |
1x9 =
9 u |
2x9 =
18 u |
The total number of markers remains unchanged. Make the total number of markers at first and in the end the same. LCM of 2 and 18 is 18.
Difference in the number of markers at first
= 13 u - 5 u
= 8 u
8 u = 72
1 u = 72 ÷ 8 = 9
Number of markers that each of them had in the end
= 18 u ÷ 2
= 9 u
Number of markers that Hilda must give to Penelope
= 9 u - 5 u
= 4 u
= 4 x 9
= 36
Answer(s): 36
