Flynn, Paul and Japheth shared a bag of stickers. Paul took 25 as many stickers as Japheth. Flynn took twice as many stickers as the total Paul and Japheth took. After Flynn had given 39 to Paul and 10 to Japheth, Paul gave 4 to Japheth. In the end, all three of them had the same number of stickers. Find the difference between the number of stickers that Flynn and Paul had at first.
| |
Paul |
Japheth |
Flynn |
Total |
| Before |
2 u |
5 u |
14 u |
21 u |
| Change 1 |
+ 39 |
|
- 39 |
|
| Change 2 |
|
+ 10 |
- 10 |
|
| Change 3 |
- 4 |
+ 4 |
|
|
| After |
1x7 =
7 u |
1x7 =
7 u |
1x7 =
7 u |
3x7 =
21 u |
Total number of stickers that Paul and Japheth had at first
= 2 u + 5 u
= 7 u
Number of stickers that Flynn had at first
= 2 x 7 u
= 14 u
The total number of stickers remains unchanged. Make the total number of stickers the same. LCM of 3 and 21 is 21.
Number of stickers that Japheth received from Paul and Flynn
= 7 u - 5 u
= 2 u
2 u = 10 + 4
2 u = 14
1 u = 14 ÷ 2 = 7
Difference between the number stickers that Flynn and Paul had at first
= 14 u - 2 u
= 12 u
= 12 x 7
= 84
Answer(s): 84
