Will, Carl and Cody shared a bag of pens. Carl took 27 as many pens as Cody. Will took four times as many pens as the total Carl and Cody took. After Will had given 82 to Carl and 44 to Cody, Carl gave 4 to Cody. In the end, all three of them had the same number of pens. Find the difference between the number of pens that Will and Carl had at first.
| |
Carl |
Cody |
Will |
Total |
| Before |
2 u |
7 u |
36 u |
45 u |
| Change 1 |
+ 82 |
|
- 82 |
|
| Change 2 |
|
+ 44 |
- 44 |
|
| Change 3 |
- 4 |
+ 4 |
|
|
| After |
1x15 =
15 u |
1x15 =
15 u |
1x15 =
15 u |
3x15 =
45 u |
Total number of pens that Carl and Cody had at first
= 2 u + 7 u
= 15 u
Number of pens that Will had at first
= 4 x 15 u
= 36 u
The total number of pens remains unchanged. Make the total number of pens the same. LCM of 3 and 45 is 45.
Number of pens that Cody received from Carl and Will
= 15 u - 7 u
= 8 u
8 u = 44 + 4
8 u = 48
1 u = 48 ÷ 8 = 6
Difference between the number pens that Will and Carl had at first
= 36 u - 2 u
= 34 u
= 34 x 6
= 204
Answer(s): 204
