Elijah, Neave and Glen shared a bag of pens. Neave took 25 as many pens as Glen. Elijah took twice as many pens as the total Neave and Glen took. After Elijah had given 32 to Neave and 3 to Glen, Neave gave 7 to Glen. In the end, all three of them had the same number of pens. Find the difference between the number of pens that Elijah and Neave had at first.
| |
Neave |
Glen |
Elijah |
Total |
| Before |
2 u |
5 u |
14 u |
21 u |
| Change 1 |
+ 32 |
|
- 32 |
|
| Change 2 |
|
+ 3 |
- 3 |
|
| Change 3 |
- 7 |
+ 7 |
|
|
| After |
1x7 =
7 u |
1x7 =
7 u |
1x7 =
7 u |
3x7 =
21 u |
Total number of pens that Neave and Glen had at first
= 2 u + 5 u
= 7 u
Number of pens that Elijah had at first
= 2 x 7 u
= 14 u
The total number of pens remains unchanged. Make the total number of pens the same. LCM of 3 and 21 is 21.
Number of pens that Glen received from Neave and Elijah
= 7 u - 5 u
= 2 u
2 u = 3 + 7
2 u = 10
1 u = 10 ÷ 2 = 5
Difference between the number pens that Elijah and Neave had at first
= 14 u - 2 u
= 12 u
= 12 x 5
= 60
Answer(s): 60
