Cole, Rael and Bryan shared a bag of beads. Rael took 27 as many beads as Bryan. Cole took thrice as many beads as the total Rael and Bryan took. After Cole had given 98 to Rael and 37 to Bryan, Rael gave 8 to Bryan. In the end, all three of them had the same number of beads. Find the difference between the number of beads that Cole and Rael had at first.
| |
Rael |
Bryan |
Cole |
Total |
| Before |
2 u |
7 u |
27 u |
36 u |
| Change 1 |
+ 98 |
|
- 98 |
|
| Change 2 |
|
+ 37 |
- 37 |
|
| Change 3 |
- 8 |
+ 8 |
|
|
| After |
1x12 =
12 u |
1x12 =
12 u |
1x12 =
12 u |
3x12 =
36 u |
Total number of beads that Rael and Bryan had at first
= 2 u + 7 u
= 12 u
Number of beads that Cole had at first
= 3 x 12 u
= 27 u
The total number of beads remains unchanged. Make the total number of beads the same. LCM of 3 and 36 is 36.
Number of beads that Bryan received from Rael and Cole
= 12 u - 7 u
= 5 u
5 u = 37 + 8
5 u = 45
1 u = 45 ÷ 5 = 9
Difference between the number beads that Cole and Rael had at first
= 27 u - 2 u
= 25 u
= 25 x 9
= 225
Answer(s): 225
