Warren, Oscar and Jeremy shared a bag of stickers. Oscar took 35 as many stickers as Jeremy. Warren took twice as many stickers as the total Oscar and Jeremy took. After Warren had given 32 to Oscar and 8 to Jeremy, Oscar gave 7 to Jeremy. In the end, all three of them had the same number of stickers. Find the difference between the number of stickers that Warren and Oscar had at first.
| |
Oscar |
Jeremy |
Warren |
Total |
| Before |
3 u |
5 u |
16 u |
24 u |
| Change 1 |
+ 32 |
|
- 32 |
|
| Change 2 |
|
+ 8 |
- 8 |
|
| Change 3 |
- 7 |
+ 7 |
|
|
| After |
1x8 =
8 u |
1x8 =
8 u |
1x8 =
8 u |
3x8 =
24 u |
Total number of stickers that Oscar and Jeremy had at first
= 3 u + 5 u
= 8 u
Number of stickers that Warren had at first
= 2 x 8 u
= 16 u
The total number of stickers remains unchanged. Make the total number of stickers the same. LCM of 3 and 24 is 24.
Number of stickers that Jeremy received from Oscar and Warren
= 8 u - 5 u
= 3 u
3 u = 8 + 7
3 u = 15
1 u = 15 ÷ 3 = 5
Difference between the number stickers that Warren and Oscar had at first
= 16 u - 3 u
= 13 u
= 13 x 5
= 65
Answer(s): 65
