Cole, Bobby and Albert shared a bag of beads. Bobby took 35 as many beads as Albert. Cole took twice as many beads as the total Bobby and Albert took. After Cole had given 47 to Bobby and 17 to Albert, Bobby gave 7 to Albert. In the end, all three of them had the same number of beads. Find the difference between the number of beads that Cole and Bobby had at first.
| |
Bobby |
Albert |
Cole |
Total |
| Before |
3 u |
5 u |
16 u |
24 u |
| Change 1 |
+ 47 |
|
- 47 |
|
| Change 2 |
|
+ 17 |
- 17 |
|
| Change 3 |
- 7 |
+ 7 |
|
|
| After |
1x8 =
8 u |
1x8 =
8 u |
1x8 =
8 u |
3x8 =
24 u |
Total number of beads that Bobby and Albert had at first
= 3 u + 5 u
= 8 u
Number of beads that Cole had at first
= 2 x 8 u
= 16 u
The total number of beads remains unchanged. Make the total number of beads the same. LCM of 3 and 24 is 24.
Number of beads that Albert received from Bobby and Cole
= 8 u - 5 u
= 3 u
3 u = 17 + 7
3 u = 24
1 u = 24 ÷ 3 = 8
Difference between the number beads that Cole and Bobby had at first
= 16 u - 3 u
= 13 u
= 13 x 8
= 104
Answer(s): 104
