Bobby, Tommy and Sam shared a bag of pens. Tommy took 35 as many pens as Sam. Bobby took twice as many pens as the total Tommy and Sam took. After Bobby had given 33 to Tommy and 15 to Sam, Tommy gave 3 to Sam. In the end, all three of them had the same number of pens. Find the difference between the number of pens that Bobby and Tommy had at first.
| |
Tommy |
Sam |
Bobby |
Total |
| Before |
3 u |
5 u |
16 u |
24 u |
| Change 1 |
+ 33 |
|
- 33 |
|
| Change 2 |
|
+ 15 |
- 15 |
|
| Change 3 |
- 3 |
+ 3 |
|
|
| After |
1x8 =
8 u |
1x8 =
8 u |
1x8 =
8 u |
3x8 =
24 u |
Total number of pens that Tommy and Sam had at first
= 3 u + 5 u
= 8 u
Number of pens that Bobby had at first
= 2 x 8 u
= 16 u
The total number of pens remains unchanged. Make the total number of pens the same. LCM of 3 and 24 is 24.
Number of pens that Sam received from Tommy and Bobby
= 8 u - 5 u
= 3 u
3 u = 15 + 3
3 u = 18
1 u = 18 ÷ 3 = 6
Difference between the number pens that Bobby and Tommy had at first
= 16 u - 3 u
= 13 u
= 13 x 6
= 78
Answer(s): 78
