Wesley, Simon and Bryan shared a bag of buttons. Simon took 35 as many buttons as Bryan. Wesley took twice as many buttons as the total Simon and Bryan took. After Wesley had given 32 to Simon and 8 to Bryan, Simon gave 7 to Bryan. In the end, all three of them had the same number of buttons. Find the difference between the number of buttons that Wesley and Simon had at first.
| |
Simon |
Bryan |
Wesley |
Total |
| Before |
3 u |
5 u |
16 u |
24 u |
| Change 1 |
+ 32 |
|
- 32 |
|
| Change 2 |
|
+ 8 |
- 8 |
|
| Change 3 |
- 7 |
+ 7 |
|
|
| After |
1x8 =
8 u |
1x8 =
8 u |
1x8 =
8 u |
3x8 =
24 u |
Total number of buttons that Simon and Bryan had at first
= 3 u + 5 u
= 8 u
Number of buttons that Wesley had at first
= 2 x 8 u
= 16 u
The total number of buttons remains unchanged. Make the total number of buttons the same. LCM of 3 and 24 is 24.
Number of buttons that Bryan received from Simon and Wesley
= 8 u - 5 u
= 3 u
3 u = 8 + 7
3 u = 15
1 u = 15 ÷ 3 = 5
Difference between the number buttons that Wesley and Simon had at first
= 16 u - 3 u
= 13 u
= 13 x 5
= 65
Answer(s): 65
