Neave, Ben and Cole shared a bag of stickers. Ben took 25 as many stickers as Cole. Neave took twice as many stickers as the total Ben and Cole took. After Neave had given 32 to Ben and 10 to Cole, Ben gave 2 to Cole. In the end, all three of them had the same number of stickers. Find the difference between the number of stickers that Neave and Ben had at first.
|
Ben |
Cole |
Neave |
Total |
Before |
2 u |
5 u |
14 u |
21 u |
Change 1 |
+ 32 |
|
- 32 |
|
Change 2 |
|
+ 10 |
- 10 |
|
Change 3 |
- 2 |
+ 2 |
|
|
After |
1x7 = 7 u |
1x7 = 7 u |
1x7 = 7 u |
3x7 = 21 u |
Total number of stickers that Ben and Cole had at first
= 2 u + 5 u
= 7 u
Number of stickers that Neave had at first
= 2 x 7 u
= 14 u
The total number of stickers remains unchanged. Make the total number of stickers the same. LCM of 3 and 21 is 21.
Number of stickers that Cole received from Ben and Neave
= 7 u - 5 u
= 2 u
2 u = 10 + 2
2 u = 12
1 u = 12 ÷ 2 = 6
Difference between the number stickers that Neave and Ben had at first
= 14 u - 2 u
= 12 u
= 12 x 6
= 72
Answer(s): 72