Vaidev, Glen and Eric shared a bag of cards. Glen took 25 as many cards as Eric. Vaidev took twice as many cards as the total Glen and Eric took. After Vaidev had given 39 to Glen and 10 to Eric, Glen gave 4 to Eric. In the end, all three of them had the same number of cards. Find the difference between the number of cards that Vaidev and Glen had at first.
| |
Glen |
Eric |
Vaidev |
Total |
| Before |
2 u |
5 u |
14 u |
21 u |
| Change 1 |
+ 39 |
|
- 39 |
|
| Change 2 |
|
+ 10 |
- 10 |
|
| Change 3 |
- 4 |
+ 4 |
|
|
| After |
1x7 =
7 u |
1x7 =
7 u |
1x7 =
7 u |
3x7 =
21 u |
Total number of cards that Glen and Eric had at first
= 2 u + 5 u
= 7 u
Number of cards that Vaidev had at first
= 2 x 7 u
= 14 u
The total number of cards remains unchanged. Make the total number of cards the same. LCM of 3 and 21 is 21.
Number of cards that Eric received from Glen and Vaidev
= 7 u - 5 u
= 2 u
2 u = 10 + 4
2 u = 14
1 u = 14 ÷ 2 = 7
Difference between the number cards that Vaidev and Glen had at first
= 14 u - 2 u
= 12 u
= 12 x 7
= 84
Answer(s): 84
