Bryan, Oscar and John shared a bag of stamps. Oscar took 27 as many stamps as John. Bryan took four times as many stamps as the total Oscar and John took. After Bryan had given 32 to Oscar and 10 to John, Oscar gave 6 to John. In the end, all three of them had the same number of stamps. Find the difference between the number of stamps that Bryan and Oscar had at first.
| |
Oscar |
John |
Bryan |
Total |
| Before |
2 u |
7 u |
36 u |
45 u |
| Change 1 |
+ 32 |
|
- 32 |
|
| Change 2 |
|
+ 10 |
- 10 |
|
| Change 3 |
- 6 |
+ 6 |
|
|
| After |
1x15 =
15 u |
1x15 =
15 u |
1x15 =
15 u |
3x15 =
45 u |
Total number of stamps that Oscar and John had at first
= 2 u + 7 u
= 15 u
Number of stamps that Bryan had at first
= 4 x 15 u
= 36 u
The total number of stamps remains unchanged. Make the total number of stamps the same. LCM of 3 and 45 is 45.
Number of stamps that John received from Oscar and Bryan
= 15 u - 7 u
= 8 u
8 u = 10 + 6
8 u = 16
1 u = 16 ÷ 8 = 2
Difference between the number stamps that Bryan and Oscar had at first
= 36 u - 2 u
= 34 u
= 34 x 2
= 68
Answer(s): 68
