Ryan, Dylan and Eric shared a bag of pens. Dylan took 27 as many pens as Eric. Ryan took four times as many pens as the total Dylan and Eric took. After Ryan had given 72 to Dylan and 33 to Eric, Dylan gave 7 to Eric. In the end, all three of them had the same number of pens. Find the difference between the number of pens that Ryan and Dylan had at first.
| |
Dylan |
Eric |
Ryan |
Total |
| Before |
2 u |
7 u |
36 u |
45 u |
| Change 1 |
+ 72 |
|
- 72 |
|
| Change 2 |
|
+ 33 |
- 33 |
|
| Change 3 |
- 7 |
+ 7 |
|
|
| After |
1x15 =
15 u |
1x15 =
15 u |
1x15 =
15 u |
3x15 =
45 u |
Total number of pens that Dylan and Eric had at first
= 2 u + 7 u
= 15 u
Number of pens that Ryan had at first
= 4 x 15 u
= 36 u
The total number of pens remains unchanged. Make the total number of pens the same. LCM of 3 and 45 is 45.
Number of pens that Eric received from Dylan and Ryan
= 15 u - 7 u
= 8 u
8 u = 33 + 7
8 u = 40
1 u = 40 ÷ 8 = 5
Difference between the number pens that Ryan and Dylan had at first
= 36 u - 2 u
= 34 u
= 34 x 5
= 170
Answer(s): 170
