Dylan, Perry and Eric shared a bag of buttons. Perry took 35 as many buttons as Eric. Dylan took twice as many buttons as the total Perry and Eric took. After Dylan had given 40 to Perry and 16 to Eric, Perry gave 5 to Eric. In the end, all three of them had the same number of buttons. Find the difference between the number of buttons that Dylan and Perry had at first.
| |
Perry |
Eric |
Dylan |
Total |
| Before |
3 u |
5 u |
16 u |
24 u |
| Change 1 |
+ 40 |
|
- 40 |
|
| Change 2 |
|
+ 16 |
- 16 |
|
| Change 3 |
- 5 |
+ 5 |
|
|
| After |
1x8 =
8 u |
1x8 =
8 u |
1x8 =
8 u |
3x8 =
24 u |
Total number of buttons that Perry and Eric had at first
= 3 u + 5 u
= 8 u
Number of buttons that Dylan had at first
= 2 x 8 u
= 16 u
The total number of buttons remains unchanged. Make the total number of buttons the same. LCM of 3 and 24 is 24.
Number of buttons that Eric received from Perry and Dylan
= 8 u - 5 u
= 3 u
3 u = 16 + 5
3 u = 21
1 u = 21 ÷ 3 = 7
Difference between the number buttons that Dylan and Perry had at first
= 16 u - 3 u
= 13 u
= 13 x 7
= 91
Answer(s): 91
