Bobby, Jack and Will shared a bag of marbles. Jack took 37 as many marbles as Will. Bobby took twice as many marbles as the total Jack and Will took. After Bobby had given 16 to Jack and 4 to Will, Jack gave 2 to Will. In the end, all three of them had the same number of marbles. Find the difference between the number of marbles that Bobby and Jack had at first.
| |
Jack |
Will |
Bobby |
Total |
| Before |
3 u |
7 u |
20 u |
30 u |
| Change 1 |
+ 16 |
|
- 16 |
|
| Change 2 |
|
+ 4 |
- 4 |
|
| Change 3 |
- 2 |
+ 2 |
|
|
| After |
1x10 =
10 u |
1x10 =
10 u |
1x10 =
10 u |
3x10 =
30 u |
Total number of marbles that Jack and Will had at first
= 3 u + 7 u
= 10 u
Number of marbles that Bobby had at first
= 2 x 10 u
= 20 u
The total number of marbles remains unchanged. Make the total number of marbles the same. LCM of 3 and 30 is 30.
Number of marbles that Will received from Jack and Bobby
= 10 u - 7 u
= 3 u
3 u = 4 + 2
3 u = 6
1 u = 6 ÷ 3 = 2
Difference between the number marbles that Bobby and Jack had at first
= 20 u - 3 u
= 17 u
= 17 x 2
= 34
Answer(s): 34
