Pierre, Neave and Tom shared a bag of stamps. Neave took 35 as many stamps as Tom. Pierre took twice as many stamps as the total Neave and Tom took. After Pierre had given 46 to Neave and 18 to Tom, Neave gave 6 to Tom. In the end, all three of them had the same number of stamps. Find the difference between the number of stamps that Pierre and Neave had at first.
| |
Neave |
Tom |
Pierre |
Total |
| Before |
3 u |
5 u |
16 u |
24 u |
| Change 1 |
+ 46 |
|
- 46 |
|
| Change 2 |
|
+ 18 |
- 18 |
|
| Change 3 |
- 6 |
+ 6 |
|
|
| After |
1x8 =
8 u |
1x8 =
8 u |
1x8 =
8 u |
3x8 =
24 u |
Total number of stamps that Neave and Tom had at first
= 3 u + 5 u
= 8 u
Number of stamps that Pierre had at first
= 2 x 8 u
= 16 u
The total number of stamps remains unchanged. Make the total number of stamps the same. LCM of 3 and 24 is 24.
Number of stamps that Tom received from Neave and Pierre
= 8 u - 5 u
= 3 u
3 u = 18 + 6
3 u = 24
1 u = 24 ÷ 3 = 8
Difference between the number stamps that Pierre and Neave had at first
= 16 u - 3 u
= 13 u
= 13 x 8
= 104
Answer(s): 104
