Jeremy, John and Cody shared a bag of cards. John took 35 as many cards as Cody. Jeremy took twice as many cards as the total John and Cody took. After Jeremy had given 60 to John and 20 to Cody, John gave 10 to Cody. In the end, all three of them had the same number of cards. Find the difference between the number of cards that Jeremy and John had at first.
| |
John |
Cody |
Jeremy |
Total |
| Before |
3 u |
5 u |
16 u |
24 u |
| Change 1 |
+ 60 |
|
- 60 |
|
| Change 2 |
|
+ 20 |
- 20 |
|
| Change 3 |
- 10 |
+ 10 |
|
|
| After |
1x8 =
8 u |
1x8 =
8 u |
1x8 =
8 u |
3x8 =
24 u |
Total number of cards that John and Cody had at first
= 3 u + 5 u
= 8 u
Number of cards that Jeremy had at first
= 2 x 8 u
= 16 u
The total number of cards remains unchanged. Make the total number of cards the same. LCM of 3 and 24 is 24.
Number of cards that Cody received from John and Jeremy
= 8 u - 5 u
= 3 u
3 u = 20 + 10
3 u = 30
1 u = 30 ÷ 3 = 10
Difference between the number cards that Jeremy and John had at first
= 16 u - 3 u
= 13 u
= 13 x 10
= 130
Answer(s): 130
