Dylan, Xavier and Ben shared a bag of stamps. Xavier took 35 as many stamps as Ben. Dylan took twice as many stamps as the total Xavier and Ben took. After Dylan had given 36 to Xavier and 12 to Ben, Xavier gave 6 to Ben. In the end, all three of them had the same number of stamps. Find the difference between the number of stamps that Dylan and Xavier had at first.
| |
Xavier |
Ben |
Dylan |
Total |
| Before |
3 u |
5 u |
16 u |
24 u |
| Change 1 |
+ 36 |
|
- 36 |
|
| Change 2 |
|
+ 12 |
- 12 |
|
| Change 3 |
- 6 |
+ 6 |
|
|
| After |
1x8 =
8 u |
1x8 =
8 u |
1x8 =
8 u |
3x8 =
24 u |
Total number of stamps that Xavier and Ben had at first
= 3 u + 5 u
= 8 u
Number of stamps that Dylan had at first
= 2 x 8 u
= 16 u
The total number of stamps remains unchanged. Make the total number of stamps the same. LCM of 3 and 24 is 24.
Number of stamps that Ben received from Xavier and Dylan
= 8 u - 5 u
= 3 u
3 u = 12 + 6
3 u = 18
1 u = 18 ÷ 3 = 6
Difference between the number stamps that Dylan and Xavier had at first
= 16 u - 3 u
= 13 u
= 13 x 6
= 78
Answer(s): 78
