Reggie, Jack and Flynn shared a bag of beads. Jack took 25 as many beads as Flynn. Reggie took twice as many beads as the total Jack and Flynn took. After Reggie had given 46 to Jack and 10 to Flynn, Jack gave 6 to Flynn. In the end, all three of them had the same number of beads. Find the difference between the number of beads that Reggie and Jack had at first.
| |
Jack |
Flynn |
Reggie |
Total |
| Before |
2 u |
5 u |
14 u |
21 u |
| Change 1 |
+ 46 |
|
- 46 |
|
| Change 2 |
|
+ 10 |
- 10 |
|
| Change 3 |
- 6 |
+ 6 |
|
|
| After |
1x7 =
7 u |
1x7 =
7 u |
1x7 =
7 u |
3x7 =
21 u |
Total number of beads that Jack and Flynn had at first
= 2 u + 5 u
= 7 u
Number of beads that Reggie had at first
= 2 x 7 u
= 14 u
The total number of beads remains unchanged. Make the total number of beads the same. LCM of 3 and 21 is 21.
Number of beads that Flynn received from Jack and Reggie
= 7 u - 5 u
= 2 u
2 u = 10 + 6
2 u = 16
1 u = 16 ÷ 2 = 8
Difference between the number beads that Reggie and Jack had at first
= 14 u - 2 u
= 12 u
= 12 x 8
= 96
Answer(s): 96
