Xavier, Neave and Valen shared a bag of stickers. Neave took 25 as many stickers as Valen. Xavier took twice as many stickers as the total Neave and Valen took. After Xavier had given 37 to Neave and 5 to Valen, Neave gave 7 to Valen. In the end, all three of them had the same number of stickers. Find the difference between the number of stickers that Xavier and Neave had at first.
| |
Neave |
Valen |
Xavier |
Total |
| Before |
2 u |
5 u |
14 u |
21 u |
| Change 1 |
+ 37 |
|
- 37 |
|
| Change 2 |
|
+ 5 |
- 5 |
|
| Change 3 |
- 7 |
+ 7 |
|
|
| After |
1x7 =
7 u |
1x7 =
7 u |
1x7 =
7 u |
3x7 =
21 u |
Total number of stickers that Neave and Valen had at first
= 2 u + 5 u
= 7 u
Number of stickers that Xavier had at first
= 2 x 7 u
= 14 u
The total number of stickers remains unchanged. Make the total number of stickers the same. LCM of 3 and 21 is 21.
Number of stickers that Valen received from Neave and Xavier
= 7 u - 5 u
= 2 u
2 u = 5 + 7
2 u = 12
1 u = 12 ÷ 2 = 6
Difference between the number stickers that Xavier and Neave had at first
= 14 u - 2 u
= 12 u
= 12 x 6
= 72
Answer(s): 72
