Harry, George and Cole shared a bag of pens. George took 27 as many pens as Cole. Harry took twice as many pens as the total George and Cole took. After Harry had given 73 to George and 8 to Cole, George gave 10 to Cole. In the end, all three of them had the same number of pens. Find the difference between the number of pens that Harry and George had at first.
| |
George |
Cole |
Harry |
Total |
| Before |
2 u |
7 u |
18 u |
27 u |
| Change 1 |
+ 73 |
|
- 73 |
|
| Change 2 |
|
+ 8 |
- 8 |
|
| Change 3 |
- 10 |
+ 10 |
|
|
| After |
1x9 =
9 u |
1x9 =
9 u |
1x9 =
9 u |
3x9 =
27 u |
Total number of pens that George and Cole had at first
= 2 u + 7 u
= 9 u
Number of pens that Harry had at first
= 2 x 9 u
= 18 u
The total number of pens remains unchanged. Make the total number of pens the same. LCM of 3 and 27 is 27.
Number of pens that Cole received from George and Harry
= 9 u - 7 u
= 2 u
2 u = 8 + 10
2 u = 18
1 u = 18 ÷ 2 = 9
Difference between the number pens that Harry and George had at first
= 18 u - 2 u
= 16 u
= 16 x 9
= 144
Answer(s): 144
