Oliver, Luis and Bobby shared a bag of beads. Luis took 25 as many beads as Bobby. Oliver took twice as many beads as the total Luis and Bobby took. After Oliver had given 40 to Luis and 2 to Bobby, Luis gave 10 to Bobby. In the end, all three of them had the same number of beads. Find the difference between the number of beads that Oliver and Luis had at first.
| |
Luis |
Bobby |
Oliver |
Total |
| Before |
2 u |
5 u |
14 u |
21 u |
| Change 1 |
+ 40 |
|
- 40 |
|
| Change 2 |
|
+ 2 |
- 2 |
|
| Change 3 |
- 10 |
+ 10 |
|
|
| After |
1x7 =
7 u |
1x7 =
7 u |
1x7 =
7 u |
3x7 =
21 u |
Total number of beads that Luis and Bobby had at first
= 2 u + 5 u
= 7 u
Number of beads that Oliver had at first
= 2 x 7 u
= 14 u
The total number of beads remains unchanged. Make the total number of beads the same. LCM of 3 and 21 is 21.
Number of beads that Bobby received from Luis and Oliver
= 7 u - 5 u
= 2 u
2 u = 2 + 10
2 u = 12
1 u = 12 ÷ 2 = 6
Difference between the number beads that Oliver and Luis had at first
= 14 u - 2 u
= 12 u
= 12 x 6
= 72
Answer(s): 72
