Brandon, Bryan and John shared a bag of stamps. Bryan took 25 as many stamps as John. Brandon took twice as many stamps as the total Bryan and John took. After Brandon had given 37 to Bryan and 12 to John, Bryan gave 2 to John. In the end, all three of them had the same number of stamps. Find the difference between the number of stamps that Brandon and Bryan had at first.
| |
Bryan |
John |
Brandon |
Total |
| Before |
2 u |
5 u |
14 u |
21 u |
| Change 1 |
+ 37 |
|
- 37 |
|
| Change 2 |
|
+ 12 |
- 12 |
|
| Change 3 |
- 2 |
+ 2 |
|
|
| After |
1x7 =
7 u |
1x7 =
7 u |
1x7 =
7 u |
3x7 =
21 u |
Total number of stamps that Bryan and John had at first
= 2 u + 5 u
= 7 u
Number of stamps that Brandon had at first
= 2 x 7 u
= 14 u
The total number of stamps remains unchanged. Make the total number of stamps the same. LCM of 3 and 21 is 21.
Number of stamps that John received from Bryan and Brandon
= 7 u - 5 u
= 2 u
2 u = 12 + 2
2 u = 14
1 u = 14 ÷ 2 = 7
Difference between the number stamps that Brandon and Bryan had at first
= 14 u - 2 u
= 12 u
= 12 x 7
= 84
Answer(s): 84
