Flynn, Ken and Seth shared a bag of beads. Ken took 25 as many beads as Seth. Flynn took twice as many beads as the total Ken and Seth took. After Flynn had given 42 to Ken and 7 to Seth, Ken gave 7 to Seth. In the end, all three of them had the same number of beads. Find the difference between the number of beads that Flynn and Ken had at first.
| |
Ken |
Seth |
Flynn |
Total |
| Before |
2 u |
5 u |
14 u |
21 u |
| Change 1 |
+ 42 |
|
- 42 |
|
| Change 2 |
|
+ 7 |
- 7 |
|
| Change 3 |
- 7 |
+ 7 |
|
|
| After |
1x7 =
7 u |
1x7 =
7 u |
1x7 =
7 u |
3x7 =
21 u |
Total number of beads that Ken and Seth had at first
= 2 u + 5 u
= 7 u
Number of beads that Flynn had at first
= 2 x 7 u
= 14 u
The total number of beads remains unchanged. Make the total number of beads the same. LCM of 3 and 21 is 21.
Number of beads that Seth received from Ken and Flynn
= 7 u - 5 u
= 2 u
2 u = 7 + 7
2 u = 14
1 u = 14 ÷ 2 = 7
Difference between the number beads that Flynn and Ken had at first
= 14 u - 2 u
= 12 u
= 12 x 7
= 84
Answer(s): 84
