Wesley, Archie and Jeremy shared a bag of pens. Archie took 27 as many pens as Jeremy. Wesley took thrice as many pens as the total Archie and Jeremy took. After Wesley had given 84 to Archie and 36 to Jeremy, Archie gave 4 to Jeremy. In the end, all three of them had the same number of pens. Find the difference between the number of pens that Wesley and Archie had at first.
| |
Archie |
Jeremy |
Wesley |
Total |
| Before |
2 u |
7 u |
27 u |
36 u |
| Change 1 |
+ 84 |
|
- 84 |
|
| Change 2 |
|
+ 36 |
- 36 |
|
| Change 3 |
- 4 |
+ 4 |
|
|
| After |
1x12 =
12 u |
1x12 =
12 u |
1x12 =
12 u |
3x12 =
36 u |
Total number of pens that Archie and Jeremy had at first
= 2 u + 7 u
= 12 u
Number of pens that Wesley had at first
= 3 x 12 u
= 27 u
The total number of pens remains unchanged. Make the total number of pens the same. LCM of 3 and 36 is 36.
Number of pens that Jeremy received from Archie and Wesley
= 12 u - 7 u
= 5 u
5 u = 36 + 4
5 u = 40
1 u = 40 ÷ 5 = 8
Difference between the number pens that Wesley and Archie had at first
= 27 u - 2 u
= 25 u
= 25 x 8
= 200
Answer(s): 200
