Cole, Perry and Charlie shared a bag of erasers. Perry took 25 as many erasers as Charlie. Cole took twice as many erasers as the total Perry and Charlie took. After Cole had given 50 to Perry and 13 to Charlie, Perry gave 5 to Charlie. In the end, all three of them had the same number of erasers. Find the difference between the number of erasers that Cole and Perry had at first.
| |
Perry |
Charlie |
Cole |
Total |
| Before |
2 u |
5 u |
14 u |
21 u |
| Change 1 |
+ 50 |
|
- 50 |
|
| Change 2 |
|
+ 13 |
- 13 |
|
| Change 3 |
- 5 |
+ 5 |
|
|
| After |
1x7 =
7 u |
1x7 =
7 u |
1x7 =
7 u |
3x7 =
21 u |
Total number of erasers that Perry and Charlie had at first
= 2 u + 5 u
= 7 u
Number of erasers that Cole had at first
= 2 x 7 u
= 14 u
The total number of erasers remains unchanged. Make the total number of erasers the same. LCM of 3 and 21 is 21.
Number of erasers that Charlie received from Perry and Cole
= 7 u - 5 u
= 2 u
2 u = 13 + 5
2 u = 18
1 u = 18 ÷ 2 = 9
Difference between the number erasers that Cole and Perry had at first
= 14 u - 2 u
= 12 u
= 12 x 9
= 108
Answer(s): 108
