Ben, Xavier and Ivan shared a bag of stamps. Xavier took 35 as many stamps as Ivan. Ben took twice as many stamps as the total Xavier and Ivan took. After Ben had given 19 to Xavier and 5 to Ivan, Xavier gave 4 to Ivan. In the end, all three of them had the same number of stamps. Find the difference between the number of stamps that Ben and Xavier had at first.
| |
Xavier |
Ivan |
Ben |
Total |
| Before |
3 u |
5 u |
16 u |
24 u |
| Change 1 |
+ 19 |
|
- 19 |
|
| Change 2 |
|
+ 5 |
- 5 |
|
| Change 3 |
- 4 |
+ 4 |
|
|
| After |
1x8 =
8 u |
1x8 =
8 u |
1x8 =
8 u |
3x8 =
24 u |
Total number of stamps that Xavier and Ivan had at first
= 3 u + 5 u
= 8 u
Number of stamps that Ben had at first
= 2 x 8 u
= 16 u
The total number of stamps remains unchanged. Make the total number of stamps the same. LCM of 3 and 24 is 24.
Number of stamps that Ivan received from Xavier and Ben
= 8 u - 5 u
= 3 u
3 u = 5 + 4
3 u = 9
1 u = 9 ÷ 3 = 3
Difference between the number stamps that Ben and Xavier had at first
= 16 u - 3 u
= 13 u
= 13 x 3
= 39
Answer(s): 39
