Oscar, Tommy and Gabriel shared a bag of stamps. Tommy took 27 as many stamps as Gabriel. Oscar took four times as many stamps as the total Tommy and Gabriel took. After Oscar had given 125 to Tommy and 64 to Gabriel, Tommy gave 8 to Gabriel. In the end, all three of them had the same number of stamps. Find the difference between the number of stamps that Oscar and Tommy had at first.
| |
Tommy |
Gabriel |
Oscar |
Total |
| Before |
2 u |
7 u |
36 u |
45 u |
| Change 1 |
+ 125 |
|
- 125 |
|
| Change 2 |
|
+ 64 |
- 64 |
|
| Change 3 |
- 8 |
+ 8 |
|
|
| After |
1x15 =
15 u |
1x15 =
15 u |
1x15 =
15 u |
3x15 =
45 u |
Total number of stamps that Tommy and Gabriel had at first
= 2 u + 7 u
= 15 u
Number of stamps that Oscar had at first
= 4 x 15 u
= 36 u
The total number of stamps remains unchanged. Make the total number of stamps the same. LCM of 3 and 45 is 45.
Number of stamps that Gabriel received from Tommy and Oscar
= 15 u - 7 u
= 8 u
8 u = 64 + 8
8 u = 72
1 u = 72 ÷ 8 = 9
Difference between the number stamps that Oscar and Tommy had at first
= 36 u - 2 u
= 34 u
= 34 x 9
= 306
Answer(s): 306
