Simon, Cody and Lee shared a bag of beads. Cody took 27 as many beads as Lee. Simon took thrice as many beads as the total Cody and Lee took. After Simon had given 64 to Cody and 26 to Lee, Cody gave 4 to Lee. In the end, all three of them had the same number of beads. Find the difference between the number of beads that Simon and Cody had at first.
| |
Cody |
Lee |
Simon |
Total |
| Before |
2 u |
7 u |
27 u |
36 u |
| Change 1 |
+ 64 |
|
- 64 |
|
| Change 2 |
|
+ 26 |
- 26 |
|
| Change 3 |
- 4 |
+ 4 |
|
|
| After |
1x12 =
12 u |
1x12 =
12 u |
1x12 =
12 u |
3x12 =
36 u |
Total number of beads that Cody and Lee had at first
= 2 u + 7 u
= 12 u
Number of beads that Simon had at first
= 3 x 12 u
= 27 u
The total number of beads remains unchanged. Make the total number of beads the same. LCM of 3 and 36 is 36.
Number of beads that Lee received from Cody and Simon
= 12 u - 7 u
= 5 u
5 u = 26 + 4
5 u = 30
1 u = 30 ÷ 5 = 6
Difference between the number beads that Simon and Cody had at first
= 27 u - 2 u
= 25 u
= 25 x 6
= 150
Answer(s): 150
