Cody, Fabian and Dylan shared a bag of cards. Fabian took 27 as many cards as Dylan. Cody took thrice as many cards as the total Fabian and Dylan took. After Cody had given 85 to Fabian and 35 to Dylan, Fabian gave 5 to Dylan. In the end, all three of them had the same number of cards. Find the difference between the number of cards that Cody and Fabian had at first.
| |
Fabian |
Dylan |
Cody |
Total |
| Before |
2 u |
7 u |
27 u |
36 u |
| Change 1 |
+ 85 |
|
- 85 |
|
| Change 2 |
|
+ 35 |
- 35 |
|
| Change 3 |
- 5 |
+ 5 |
|
|
| After |
1x12 =
12 u |
1x12 =
12 u |
1x12 =
12 u |
3x12 =
36 u |
Total number of cards that Fabian and Dylan had at first
= 2 u + 7 u
= 12 u
Number of cards that Cody had at first
= 3 x 12 u
= 27 u
The total number of cards remains unchanged. Make the total number of cards the same. LCM of 3 and 36 is 36.
Number of cards that Dylan received from Fabian and Cody
= 12 u - 7 u
= 5 u
5 u = 35 + 5
5 u = 40
1 u = 40 ÷ 5 = 8
Difference between the number cards that Cody and Fabian had at first
= 27 u - 2 u
= 25 u
= 25 x 8
= 200
Answer(s): 200
