Nick, Ahmad and Ben shared a bag of coins. Ahmad took 25 as many coins as Ben. Nick took twice as many coins as the total Ahmad and Ben took. After Nick had given 43 to Ahmad and 13 to Ben, Ahmad gave 3 to Ben. In the end, all three of them had the same number of coins. Find the difference between the number of coins that Nick and Ahmad had at first.
| |
Ahmad |
Ben |
Nick |
Total |
| Before |
2 u |
5 u |
14 u |
21 u |
| Change 1 |
+ 43 |
|
- 43 |
|
| Change 2 |
|
+ 13 |
- 13 |
|
| Change 3 |
- 3 |
+ 3 |
|
|
| After |
1x7 =
7 u |
1x7 =
7 u |
1x7 =
7 u |
3x7 =
21 u |
Total number of coins that Ahmad and Ben had at first
= 2 u + 5 u
= 7 u
Number of coins that Nick had at first
= 2 x 7 u
= 14 u
The total number of coins remains unchanged. Make the total number of coins the same. LCM of 3 and 21 is 21.
Number of coins that Ben received from Ahmad and Nick
= 7 u - 5 u
= 2 u
2 u = 13 + 3
2 u = 16
1 u = 16 ÷ 2 = 8
Difference between the number coins that Nick and Ahmad had at first
= 14 u - 2 u
= 12 u
= 12 x 8
= 96
Answer(s): 96
