John, Justin and Glen shared a bag of pens. Justin took 25 as many pens as Glen. John took twice as many pens as the total Justin and Glen took. After John had given 50 to Justin and 6 to Glen, Justin gave 10 to Glen. In the end, all three of them had the same number of pens. Find the difference between the number of pens that John and Justin had at first.
| |
Justin |
Glen |
John |
Total |
| Before |
2 u |
5 u |
14 u |
21 u |
| Change 1 |
+ 50 |
|
- 50 |
|
| Change 2 |
|
+ 6 |
- 6 |
|
| Change 3 |
- 10 |
+ 10 |
|
|
| After |
1x7 =
7 u |
1x7 =
7 u |
1x7 =
7 u |
3x7 =
21 u |
Total number of pens that Justin and Glen had at first
= 2 u + 5 u
= 7 u
Number of pens that John had at first
= 2 x 7 u
= 14 u
The total number of pens remains unchanged. Make the total number of pens the same. LCM of 3 and 21 is 21.
Number of pens that Glen received from Justin and John
= 7 u - 5 u
= 2 u
2 u = 6 + 10
2 u = 16
1 u = 16 ÷ 2 = 8
Difference between the number pens that John and Justin had at first
= 14 u - 2 u
= 12 u
= 12 x 8
= 96
Answer(s): 96
