Oliver, Asher and Bryan shared a bag of beads. Asher took 37 as many beads as Bryan. Oliver took twice as many beads as the total Asher and Bryan took. After Oliver had given 72 to Asher and 28 to Bryan, Asher gave 2 to Bryan. In the end, all three of them had the same number of beads. Find the difference between the number of beads that Oliver and Asher had at first.
| |
Asher |
Bryan |
Oliver |
Total |
| Before |
3 u |
7 u |
20 u |
30 u |
| Change 1 |
+ 72 |
|
- 72 |
|
| Change 2 |
|
+ 28 |
- 28 |
|
| Change 3 |
- 2 |
+ 2 |
|
|
| After |
1x10 =
10 u |
1x10 =
10 u |
1x10 =
10 u |
3x10 =
30 u |
Total number of beads that Asher and Bryan had at first
= 3 u + 7 u
= 10 u
Number of beads that Oliver had at first
= 2 x 10 u
= 20 u
The total number of beads remains unchanged. Make the total number of beads the same. LCM of 3 and 30 is 30.
Number of beads that Bryan received from Asher and Oliver
= 10 u - 7 u
= 3 u
3 u = 28 + 2
3 u = 30
1 u = 30 ÷ 3 = 10
Difference between the number beads that Oliver and Asher had at first
= 20 u - 3 u
= 17 u
= 17 x 10
= 170
Answer(s): 170
