Perry, Carl and Luis shared a bag of erasers. Carl took 35 as many erasers as Luis. Perry took twice as many erasers as the total Carl and Luis took. After Perry had given 30 to Carl and 2 to Luis, Carl gave 10 to Luis. In the end, all three of them had the same number of erasers. Find the difference between the number of erasers that Perry and Carl had at first.
| |
Carl |
Luis |
Perry |
Total |
| Before |
3 u |
5 u |
16 u |
24 u |
| Change 1 |
+ 30 |
|
- 30 |
|
| Change 2 |
|
+ 2 |
- 2 |
|
| Change 3 |
- 10 |
+ 10 |
|
|
| After |
1x8 =
8 u |
1x8 =
8 u |
1x8 =
8 u |
3x8 =
24 u |
Total number of erasers that Carl and Luis had at first
= 3 u + 5 u
= 8 u
Number of erasers that Perry had at first
= 2 x 8 u
= 16 u
The total number of erasers remains unchanged. Make the total number of erasers the same. LCM of 3 and 24 is 24.
Number of erasers that Luis received from Carl and Perry
= 8 u - 5 u
= 3 u
3 u = 2 + 10
3 u = 12
1 u = 12 ÷ 3 = 4
Difference between the number erasers that Perry and Carl had at first
= 16 u - 3 u
= 13 u
= 13 x 4
= 52
Answer(s): 52
