Carl, Brandon and Ian shared a bag of erasers. Brandon took 25 as many erasers as Ian. Carl took twice as many erasers as the total Brandon and Ian took. After Carl had given 33 to Brandon and 2 to Ian, Brandon gave 8 to Ian. In the end, all three of them had the same number of erasers. Find the difference between the number of erasers that Carl and Brandon had at first.
| |
Brandon |
Ian |
Carl |
Total |
| Before |
2 u |
5 u |
14 u |
21 u |
| Change 1 |
+ 33 |
|
- 33 |
|
| Change 2 |
|
+ 2 |
- 2 |
|
| Change 3 |
- 8 |
+ 8 |
|
|
| After |
1x7 =
7 u |
1x7 =
7 u |
1x7 =
7 u |
3x7 =
21 u |
Total number of erasers that Brandon and Ian had at first
= 2 u + 5 u
= 7 u
Number of erasers that Carl had at first
= 2 x 7 u
= 14 u
The total number of erasers remains unchanged. Make the total number of erasers the same. LCM of 3 and 21 is 21.
Number of erasers that Ian received from Brandon and Carl
= 7 u - 5 u
= 2 u
2 u = 2 + 8
2 u = 10
1 u = 10 ÷ 2 = 5
Difference between the number erasers that Carl and Brandon had at first
= 14 u - 2 u
= 12 u
= 12 x 5
= 60
Answer(s): 60
