Pierre, Lee and Reggie shared a bag of stamps. Lee took 37 as many stamps as Reggie. Pierre took twice as many stamps as the total Lee and Reggie took. After Pierre had given 59 to Lee and 11 to Reggie, Lee gave 10 to Reggie. In the end, all three of them had the same number of stamps. Find the difference between the number of stamps that Pierre and Lee had at first.
| |
Lee |
Reggie |
Pierre |
Total |
| Before |
3 u |
7 u |
20 u |
30 u |
| Change 1 |
+ 59 |
|
- 59 |
|
| Change 2 |
|
+ 11 |
- 11 |
|
| Change 3 |
- 10 |
+ 10 |
|
|
| After |
1x10 =
10 u |
1x10 =
10 u |
1x10 =
10 u |
3x10 =
30 u |
Total number of stamps that Lee and Reggie had at first
= 3 u + 7 u
= 10 u
Number of stamps that Pierre had at first
= 2 x 10 u
= 20 u
The total number of stamps remains unchanged. Make the total number of stamps the same. LCM of 3 and 30 is 30.
Number of stamps that Reggie received from Lee and Pierre
= 10 u - 7 u
= 3 u
3 u = 11 + 10
3 u = 21
1 u = 21 ÷ 3 = 7
Difference between the number stamps that Pierre and Lee had at first
= 20 u - 3 u
= 17 u
= 17 x 7
= 119
Answer(s): 119
