Rael, Bobby and Bryan shared a bag of marbles. Bobby took 25 as many marbles as Bryan. Rael took twice as many marbles as the total Bobby and Bryan took. After Rael had given 33 to Bobby and 2 to Bryan, Bobby gave 8 to Bryan. In the end, all three of them had the same number of marbles. Find the difference between the number of marbles that Rael and Bobby had at first.
| |
Bobby |
Bryan |
Rael |
Total |
| Before |
2 u |
5 u |
14 u |
21 u |
| Change 1 |
+ 33 |
|
- 33 |
|
| Change 2 |
|
+ 2 |
- 2 |
|
| Change 3 |
- 8 |
+ 8 |
|
|
| After |
1x7 =
7 u |
1x7 =
7 u |
1x7 =
7 u |
3x7 =
21 u |
Total number of marbles that Bobby and Bryan had at first
= 2 u + 5 u
= 7 u
Number of marbles that Rael had at first
= 2 x 7 u
= 14 u
The total number of marbles remains unchanged. Make the total number of marbles the same. LCM of 3 and 21 is 21.
Number of marbles that Bryan received from Bobby and Rael
= 7 u - 5 u
= 2 u
2 u = 2 + 8
2 u = 10
1 u = 10 ÷ 2 = 5
Difference between the number marbles that Rael and Bobby had at first
= 14 u - 2 u
= 12 u
= 12 x 5
= 60
Answer(s): 60
