Dylan, Elijah and Harry shared a bag of pens. Elijah took 37 as many pens as Harry. Dylan took twice as many pens as the total Elijah and Harry took. After Dylan had given 68 to Elijah and 22 to Harry, Elijah gave 5 to Harry. In the end, all three of them had the same number of pens. Find the difference between the number of pens that Dylan and Elijah had at first.
| |
Elijah |
Harry |
Dylan |
Total |
| Before |
3 u |
7 u |
20 u |
30 u |
| Change 1 |
+ 68 |
|
- 68 |
|
| Change 2 |
|
+ 22 |
- 22 |
|
| Change 3 |
- 5 |
+ 5 |
|
|
| After |
1x10 =
10 u |
1x10 =
10 u |
1x10 =
10 u |
3x10 =
30 u |
Total number of pens that Elijah and Harry had at first
= 3 u + 7 u
= 10 u
Number of pens that Dylan had at first
= 2 x 10 u
= 20 u
The total number of pens remains unchanged. Make the total number of pens the same. LCM of 3 and 30 is 30.
Number of pens that Harry received from Elijah and Dylan
= 10 u - 7 u
= 3 u
3 u = 22 + 5
3 u = 27
1 u = 27 ÷ 3 = 9
Difference between the number pens that Dylan and Elijah had at first
= 20 u - 3 u
= 17 u
= 17 x 9
= 153
Answer(s): 153
