Paul, Seth and Tim shared a bag of stamps. Seth took 25 as many stamps as Tim. Paul took twice as many stamps as the total Seth and Tim took. After Paul had given 47 to Seth and 9 to Tim, Seth gave 7 to Tim. In the end, all three of them had the same number of stamps. Find the difference between the number of stamps that Paul and Seth had at first.
| |
Seth |
Tim |
Paul |
Total |
| Before |
2 u |
5 u |
14 u |
21 u |
| Change 1 |
+ 47 |
|
- 47 |
|
| Change 2 |
|
+ 9 |
- 9 |
|
| Change 3 |
- 7 |
+ 7 |
|
|
| After |
1x7 =
7 u |
1x7 =
7 u |
1x7 =
7 u |
3x7 =
21 u |
Total number of stamps that Seth and Tim had at first
= 2 u + 5 u
= 7 u
Number of stamps that Paul had at first
= 2 x 7 u
= 14 u
The total number of stamps remains unchanged. Make the total number of stamps the same. LCM of 3 and 21 is 21.
Number of stamps that Tim received from Seth and Paul
= 7 u - 5 u
= 2 u
2 u = 9 + 7
2 u = 16
1 u = 16 ÷ 2 = 8
Difference between the number stamps that Paul and Seth had at first
= 14 u - 2 u
= 12 u
= 12 x 8
= 96
Answer(s): 96
