Ryan, Flynn and Julian shared a bag of pens. Flynn took 25 as many pens as Julian. Ryan took twice as many pens as the total Flynn and Julian took. After Ryan had given 52 to Flynn and 18 to Julian, Flynn gave 2 to Julian. In the end, all three of them had the same number of pens. Find the difference between the number of pens that Ryan and Flynn had at first.
| |
Flynn |
Julian |
Ryan |
Total |
| Before |
2 u |
5 u |
14 u |
21 u |
| Change 1 |
+ 52 |
|
- 52 |
|
| Change 2 |
|
+ 18 |
- 18 |
|
| Change 3 |
- 2 |
+ 2 |
|
|
| After |
1x7 =
7 u |
1x7 =
7 u |
1x7 =
7 u |
3x7 =
21 u |
Total number of pens that Flynn and Julian had at first
= 2 u + 5 u
= 7 u
Number of pens that Ryan had at first
= 2 x 7 u
= 14 u
The total number of pens remains unchanged. Make the total number of pens the same. LCM of 3 and 21 is 21.
Number of pens that Julian received from Flynn and Ryan
= 7 u - 5 u
= 2 u
2 u = 18 + 2
2 u = 20
1 u = 20 ÷ 2 = 10
Difference between the number pens that Ryan and Flynn had at first
= 14 u - 2 u
= 12 u
= 12 x 10
= 120
Answer(s): 120
