Seth, Ahmad and Zane shared a bag of stickers. Ahmad took 37 as many stickers as Zane. Seth took twice as many stickers as the total Ahmad and Zane took. After Seth had given 72 to Ahmad and 28 to Zane, Ahmad gave 2 to Zane. In the end, all three of them had the same number of stickers. Find the difference between the number of stickers that Seth and Ahmad had at first.
| |
Ahmad |
Zane |
Seth |
Total |
| Before |
3 u |
7 u |
20 u |
30 u |
| Change 1 |
+ 72 |
|
- 72 |
|
| Change 2 |
|
+ 28 |
- 28 |
|
| Change 3 |
- 2 |
+ 2 |
|
|
| After |
1x10 =
10 u |
1x10 =
10 u |
1x10 =
10 u |
3x10 =
30 u |
Total number of stickers that Ahmad and Zane had at first
= 3 u + 7 u
= 10 u
Number of stickers that Seth had at first
= 2 x 10 u
= 20 u
The total number of stickers remains unchanged. Make the total number of stickers the same. LCM of 3 and 30 is 30.
Number of stickers that Zane received from Ahmad and Seth
= 10 u - 7 u
= 3 u
3 u = 28 + 2
3 u = 30
1 u = 30 ÷ 3 = 10
Difference between the number stickers that Seth and Ahmad had at first
= 20 u - 3 u
= 17 u
= 17 x 10
= 170
Answer(s): 170
