Dylan, Ivan and Andy shared a bag of stickers. Ivan took 27 as many stickers as Andy. Dylan took thrice as many stickers as the total Ivan and Andy took. After Dylan had given 82 to Ivan and 38 to Andy, Ivan gave 2 to Andy. In the end, all three of them had the same number of stickers. Find the difference between the number of stickers that Dylan and Ivan had at first.
| |
Ivan |
Andy |
Dylan |
Total |
| Before |
2 u |
7 u |
27 u |
36 u |
| Change 1 |
+ 82 |
|
- 82 |
|
| Change 2 |
|
+ 38 |
- 38 |
|
| Change 3 |
- 2 |
+ 2 |
|
|
| After |
1x12 =
12 u |
1x12 =
12 u |
1x12 =
12 u |
3x12 =
36 u |
Total number of stickers that Ivan and Andy had at first
= 2 u + 7 u
= 12 u
Number of stickers that Dylan had at first
= 3 x 12 u
= 27 u
The total number of stickers remains unchanged. Make the total number of stickers the same. LCM of 3 and 36 is 36.
Number of stickers that Andy received from Ivan and Dylan
= 12 u - 7 u
= 5 u
5 u = 38 + 2
5 u = 40
1 u = 40 ÷ 5 = 8
Difference between the number stickers that Dylan and Ivan had at first
= 27 u - 2 u
= 25 u
= 25 x 8
= 200
Answer(s): 200
