Cody, Gabriel and Albert shared a bag of stickers. Gabriel took 27 as many stickers as Albert. Cody took thrice as many stickers as the total Gabriel and Albert took. After Cody had given 95 to Gabriel and 40 to Albert, Gabriel gave 5 to Albert. In the end, all three of them had the same number of stickers. Find the difference between the number of stickers that Cody and Gabriel had at first.
| |
Gabriel |
Albert |
Cody |
Total |
| Before |
2 u |
7 u |
27 u |
36 u |
| Change 1 |
+ 95 |
|
- 95 |
|
| Change 2 |
|
+ 40 |
- 40 |
|
| Change 3 |
- 5 |
+ 5 |
|
|
| After |
1x12 =
12 u |
1x12 =
12 u |
1x12 =
12 u |
3x12 =
36 u |
Total number of stickers that Gabriel and Albert had at first
= 2 u + 7 u
= 12 u
Number of stickers that Cody had at first
= 3 x 12 u
= 27 u
The total number of stickers remains unchanged. Make the total number of stickers the same. LCM of 3 and 36 is 36.
Number of stickers that Albert received from Gabriel and Cody
= 12 u - 7 u
= 5 u
5 u = 40 + 5
5 u = 45
1 u = 45 ÷ 5 = 9
Difference between the number stickers that Cody and Gabriel had at first
= 27 u - 2 u
= 25 u
= 25 x 9
= 225
Answer(s): 225
