Xavier, Tom and Simon shared a bag of stickers. Tom took 27 as many stickers as Simon. Xavier took four times as many stickers as the total Tom and Simon took. After Xavier had given 44 to Tom and 19 to Simon, Tom gave 5 to Simon. In the end, all three of them had the same number of stickers. Find the difference between the number of stickers that Xavier and Tom had at first.
| |
Tom |
Simon |
Xavier |
Total |
| Before |
2 u |
7 u |
36 u |
45 u |
| Change 1 |
+ 44 |
|
- 44 |
|
| Change 2 |
|
+ 19 |
- 19 |
|
| Change 3 |
- 5 |
+ 5 |
|
|
| After |
1x15 =
15 u |
1x15 =
15 u |
1x15 =
15 u |
3x15 =
45 u |
Total number of stickers that Tom and Simon had at first
= 2 u + 7 u
= 15 u
Number of stickers that Xavier had at first
= 4 x 15 u
= 36 u
The total number of stickers remains unchanged. Make the total number of stickers the same. LCM of 3 and 45 is 45.
Number of stickers that Simon received from Tom and Xavier
= 15 u - 7 u
= 8 u
8 u = 19 + 5
8 u = 24
1 u = 24 ÷ 8 = 3
Difference between the number stickers that Xavier and Tom had at first
= 36 u - 2 u
= 34 u
= 34 x 3
= 102
Answer(s): 102
