Jeremy, Warren and Gabriel shared a bag of stickers. Warren took 27 as many stickers as Gabriel. Jeremy took thrice as many stickers as the total Warren and Gabriel took. After Jeremy had given 78 to Warren and 27 to Gabriel, Warren gave 8 to Gabriel. In the end, all three of them had the same number of stickers. Find the difference between the number of stickers that Jeremy and Warren had at first.
| |
Warren |
Gabriel |
Jeremy |
Total |
| Before |
2 u |
7 u |
27 u |
36 u |
| Change 1 |
+ 78 |
|
- 78 |
|
| Change 2 |
|
+ 27 |
- 27 |
|
| Change 3 |
- 8 |
+ 8 |
|
|
| After |
1x12 =
12 u |
1x12 =
12 u |
1x12 =
12 u |
3x12 =
36 u |
Total number of stickers that Warren and Gabriel had at first
= 2 u + 7 u
= 12 u
Number of stickers that Jeremy had at first
= 3 x 12 u
= 27 u
The total number of stickers remains unchanged. Make the total number of stickers the same. LCM of 3 and 36 is 36.
Number of stickers that Gabriel received from Warren and Jeremy
= 12 u - 7 u
= 5 u
5 u = 27 + 8
5 u = 35
1 u = 35 ÷ 5 = 7
Difference between the number stickers that Jeremy and Warren had at first
= 27 u - 2 u
= 25 u
= 25 x 7
= 175
Answer(s): 175
